How far is San Andros from Cleveland, OH?

The distance between Cleveland (Cleveland Hopkins International Airport) and San Andros (San Andros Airport) is 1148 miles / 1848 kilometers / 998 nautical miles.

Distance from Cleveland to San Andros

There are several ways to calculate the distance from Cleveland to San Andros. Here are two standard methods:

Vincenty's formula (applied above)

• 1148.301 miles
• 1848.011 kilometers
• 997.846 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula

• 1151.042 miles
• 1852.422 kilometers
• 1000.228 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Cleveland to San Andros?

The estimated flight time from Cleveland Hopkins International Airport to San Andros Airport is 2 hours and 40 minutes.

What is the time difference between Cleveland and San Andros?

There is no time difference between Cleveland and San Andros.

Flight carbon footprint between Cleveland Hopkins International Airport (CLE) and San Andros Airport (SAQ)

On average, flying from Cleveland to San Andros generates about 159 kg of CO2 per passenger, and 159 kilograms equals 351 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Cleveland to San Andros

See the map of the shortest flight path between Cleveland Hopkins International Airport (CLE) and San Andros Airport (SAQ).

Airport information

Origin	Cleveland Hopkins International Airport
City:	Cleveland, OH
Country:	United States
IATA Code:	CLE
ICAO Code:	KCLE
Coordinates:	41°24′42″N, 81°50′59″W

Destination	San Andros Airport
City:	San Andros
Country:	Bahamas
IATA Code:	SAQ
ICAO Code:	MYAN
Coordinates:	25°3′13″N, 78°2′56″W