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How far is Galapagos from Cuenca?

The distance between Cuenca (Mariscal Lamar International Airport) and Galapagos (Seymour Airport) is 798 miles / 1284 kilometers / 693 nautical miles.

Mariscal Lamar International Airport – Seymour Airport

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798
Miles
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1284
Kilometers
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693
Nautical miles

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Distance from Cuenca to Galapagos

There are several ways to calculate the distance from Cuenca to Galapagos. Here are two standard methods:

Vincenty's formula (applied above)
  • 797.712 miles
  • 1283.794 kilometers
  • 693.193 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth's surface using an ellipsoidal model of the planet.

Haversine formula
  • 797.055 miles
  • 1282.736 kilometers
  • 692.622 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

How long does it take to fly from Cuenca to Galapagos?

The estimated flight time from Mariscal Lamar International Airport to Seymour Airport is 2 hours and 0 minutes.

Flight carbon footprint between Mariscal Lamar International Airport (CUE) and Seymour Airport (GPS)

On average, flying from Cuenca to Galapagos generates about 135 kg of CO2 per passenger, and 135 kilograms equals 297 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

Map of flight path from Cuenca to Galapagos

See the map of the shortest flight path between Mariscal Lamar International Airport (CUE) and Seymour Airport (GPS).

Airport information

Origin Mariscal Lamar International Airport
City: Cuenca
Country: Ecuador Flag of Ecuador
IATA Code: CUE
ICAO Code: SECU
Coordinates: 2°53′22″S, 78°59′3″W
Destination Seymour Airport
City: Galapagos
Country: Ecuador Flag of Ecuador
IATA Code: GPS
ICAO Code: SEGS
Coordinates: 0°27′13″S, 90°15′57″W