# Distance between Plaisance (MRU) and Zhukovsky (ZIA)

Flight distance from Plaisance to Zhukovsky (Port Louis Sir Seewoosagur Ramgoolam International Airport – Zhukovsky International Airport) is 5356 miles / 8620 kilometers / 4654 nautical miles. Estimated flight time is 10 hours 38 minutes.

## Map of flight path from Plaisance to Zhukovsky.

Shortest flight path between Port Louis Sir Seewoosagur Ramgoolam International Airport (MRU) and Zhukovsky International Airport (ZIA).

## How far is Zhukovsky from Plaisance?

There are several ways to calculate distances between Plaisance and Zhukovsky. Here are two common methods:

Vincenty's formula (applied above)
• 5356.070 miles
• 8619.759 kilometers
• 4654.297 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth’s surface, using an ellipsoidal model of the earth.

Haversine formula
• 5373.972 miles
• 8648.570 kilometers
• 4669.854 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

## Airport information

A Port Louis Sir Seewoosagur Ramgoolam International Airport
City: Plaisance
Country: Mauritius
IATA Code: MRU
ICAO Code: FIMP
Coordinates: 20°25′48″S, 57°41′0″E

B Zhukovsky International Airport
City: Zhukovsky
Country: Russia
IATA Code: ZIA
ICAO Code: UUBW
Coordinates: 55°33′11″N, 38°9′0″E

## Time difference and current local times

The time difference between Plaisance and Zhukovsky is 1 hour. Zhukovsky is 1 hour behind Plaisance.

+04

MSK

## Carbon dioxide emissions

Estimated CO2 emissions per passenger is 631 kg (1 390 pounds).

## Frequent Flyer Miles Calculator

Plaisance (MRU) → Zhukovsky (ZIA).

Distance:
5356
Elite level bonus:
0
Booking class bonus:
0

### In total

Total frequent flyer miles:
5356

Round trip?