# Distance between Pakse (PKZ) and Sainyabuli (ZBY)

Flight distance from Pakse to Sainyabuli (Pakse International Airport – Sayaboury Airport) is 390 miles / 628 kilometers / 339 nautical miles. Estimated flight time is 1 hour 14 minutes.

Driving distance from Pakse (PKZ) to Sainyabuli (ZBY) is 596 miles / 959 kilometers and travel time by car is about 13 hours 51 minutes.

390
Miles
628
Kilometers
339
Nautical miles
1 h 14 min

## How far is Sainyabuli from Pakse?

There are several ways to calculate distances between Los Angeles and Chicago. Here are two common methods:

Vincenty's formula (applied above)
• 390.305 miles
• 628.134 kilometers
• 339.165 nautical miles

Vincenty's formula calculates the distance between latitude/longitude points on the earth’s surface, using an ellipsoidal model of the earth.

Haversine formula
• 391.013 miles
• 629.275 kilometers
• 339.781 nautical miles

The haversine formula calculates the distance between latitude/longitude points assuming a spherical earth (great-circle distance – the shortest distance between two points).

## Flight Duration

Estimated flight time from Pakse International Airport to Sayaboury Airport is 1 hour 14 minutes.

## Time difference

There is no time difference between Pakse and Sainyabuli.

## Carbon dioxide emissions

On average flying from Pakse to Sainyabuli generates about 82 kg of CO2 per passenger, 82 kilograms is equal to 182 pounds (lbs). The figures are estimates and include only the CO2 generated by burning jet fuel.

## Map of flight path and driving directions from Pakse to Sainyabuli

Shortest flight path between Pakse International Airport (PKZ) and Sayaboury Airport (ZBY).

## Airport information

Origin Pakse International Airport
City: Pakse
Country: Laos
IATA Code: PKZ
ICAO Code: VLPS
Coordinates: 15°7′55″N, 105°46′51″E
Destination Sayaboury Airport
City: Sainyabuli
Country: Laos
IATA Code: ZBY
ICAO Code: VLSB
Coordinates: 19°14′36″N, 101°42′33″E